Automobile batteries use 3.0 m h2so4 as an electrolyte. how much 1.20 m naoh will be needed to neutralize 225 ml of battery acid? h2so4(aq) + 2naoh(aq) --> 2h2o(l) + na2so4(aq)

Answer : The volume of the needed are, 1125 ml

Explanation :

Using neutralization law,

where,

= basicity of an acid = 2

= acidity of a base = 1

= concentration of = 3.0 M

= concentration of NaOH = 1.20 M

= volume of = 225 ml

= volume of NaOH = ?

Now put all the given values in the above law, we get the volume of the .

Therefore, the volume of the needed are, 1125 ml

idk i'm not smart

explanation:

t h