Given the following masses, calculate the mass of water lost & determine the percent hydration.
mass of hydrate: 10.24g
mass of anhydrate: 8.74g
mass of water lost: ?
percent hydration: ?
i got 1.50g for mass of water lost & 15% for percent hydration but i just want to make sure. show how you got the answers. you! (:

You are given the mass of hydrate which is 10.24g and the mass of anhydrate which is 8.74g. Hydrate means that it contains water and anhydrate means the substance has lost water during the process. So you just subtract them, 10.24g – 8.74g = 1.5g of water is lost. Percent hydration is equal to one subtracted to the mass of anhydrate divided by the mass of hydrate multiplied by 100. So we have, [1-(8.74g/10.24g)] *100 = 14.65% or 15%. Your answers are correct.

Only one reactant yields 2 or more products. meaning you will only have 1 product and it will break down into 2 or more products. eg. h2o -> h2 + o2