To answer this question use the hydrazine-nitrogen tetroxide rocket fuel reaction: 2n2h4 + n2o4 = 3n2 + 4h2o. how many moles of n2h4 are needed to react with 4 moles of n2o4 a) 4 moles b) 2 moles c) 8 moles d) 6 moles

The   moles  of  N2H4  needed  to  react  with  4  moles   of  N2O4  is  calculated   as  follows

from  the  reacting  equation

2N2H4  +  N2O4  >  3N2  +  4  H2O

the reacting  ratio  between    N2H4  to  N2O4  is   2  :1,  therefore  the   moles  of  N2O4  is  =  4moles  x 2  =  8  moles

Yes i think so not 100 percent sure though

They are all full and don't need any more electrons in there outer shell.