Astrong monoprotic acid ionizes in water. if the [h3o+] concentration is 1.56 x 10-4 m, what else is true?

If,
              [H⁺]  =  1.56 × 10⁻⁴ M
Then,
              pH  = -log (1.56 × 10⁻⁴)

              pH  =  3.80
Also,
              pH + pOH  =  14
So,
              pOH  =  14- 3.80

              pOH  =  10.2

Taking Anti log of pOH,
            
              [OH⁻]  = 10⁻¹⁰°²

              [OH⁻]  =  6.30 × 10⁻¹¹

Result:
           For [H⁺] = 1.56 × 10⁻⁴ other true statements are,

                        1)  [OH⁻]  =  6.30 × 10⁻¹¹

                        2)  pH  =  3.80

                        3)  pOH  =  10.2

Woah that’s a lot to read xd i’ll try though. i’ll get back t you if. i know the andwer