Write the condensed electron configurations for the ga atom. express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, [he]2s22p2 should be entered as [he]2s^22p^2.

Gallium element with symbol Ga has an atomic number of 31.
Electrons start filling orbitals in increasing energy levels.
First energy shell contains the s orbital which can hold only 2 electrons.
Second energy shell contains a both p orbital and s orbital, p orbital can hold upto 6 electrons, so a total of 8 electrons in the 2nd shell.
Third energy shell contains s, p and d orbital. d orbital can hold upto 10 electrons, so the third shell can hold up to 18 electrons.
electronic configuration of Ga is 1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^1
we are asked to write in the condensed form, which means we have to write the noble gas with the nearest electronic configuration to Ga.
Noble gas with electronic configuration closest to Ga is argon with atomic number 18.
Ar  - 1s^2 2s^2 2p^6 3s^2 3p^6 
Ga in condensed form - [Ar] 3d^10 4s^2 4p^1