Quais são os símbolos dos quatro números quânticos usados na especificação de elétrons em átomos?

Question:

               What are the symbols of the four quantum numbers used in the specification of electrons in atoms?

              The four Quantum Numbers along with Symbol and brief explanation are as follow,

1) Principal Quantum Number:

          Symbol = n

This quantum number explains the main energy level or main shell in which an electron is present.

2) Azimuthal Quantum Number:

          Symbol = l

This quantum number is associated with principal quantum number and it represents the sub energy levels or sub shells.

3) Magnetic Quantum Number:

          Symbol = m

This quantum number explains the magnetic properties of an atom. Electrons with different magnetic quantum numbers have different orientations in applied magnetic field.

4) Spin Quantum Number:

          Symbol = s

This quantum number explain the spin of an electron about its axis. The spin may be clockwise or anti-clockwise.

answer; protein;

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.