For the vaporization reaction br2(l) → br2( g., δh0= 31.0 kj/mol and δs0 = 93.0 j/(mol • k). at what temperature will this process be spontaneous? \

    The  temperature  at   which  the  process  be   spontaneous  is  calculated  as  follows

delta  G  =  delta H  -T delta S

let  delta G  be =0

therefore  delta H- T  delta s =0

therefore  T=  delta  H/  delta  S
convert  31   Kj  to  J  =  31  x1000=  31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K

Ais the correct answer