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)![pH=pKa + log ( \frac{[A^{-}] }{[HA]} ) \\ \\ pH=4,19 + log ( \frac{0,05M}{0,05M}) \\ \\ pH=4,19](/tpl/images/0137/1803/3e5ee.png)
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Calculate the ph of 100 ml of a buffer solution containing 0.05 m benzoic acid (c6h5co2h; ka = 6.4...
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