Balance the following redox equation and identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. show all of the work used to solve the problem. cn- + mno4- yields cno- + mno2

Solution:
Mn+7O-24- + C+2N-3- → Mn+4O-22 + C+4N-3O-2-

O:C+2N-3- → C+4N-3O-2- + 2e- (C)
R:Mn+7O-24- + 3e- → Mn+4O-22 (Mn

O:C+2N-3- → C+4N-3O-2- + 2e-
R:Mn+7O-24- + 3e- → Mn+4O-22

3C+2N-3- + 2Mn+7O-24- + 6OH- + 6e- + 4H2O → 3C+4N-3O-2- + 2Mn+4O-22 + 6e- + 8OH- + 3H2O

CHECK
3*1C 3*1
3*1N 3*1
2*1Mn 2*1
9 O 9
1*2 H 2*1

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.