Consider the combustion of liquid methanol, ch3oh(l): ch3oh(l)+3/2o2(g)→co2(g)+2h2o(l)δh= −726.5kj part a what is the enthalpy change for the reverse reaction?

For any reaction the enthalpy change in the forward direction and enthalpy change in reverse direction is equal in magnitude and opposite in sign .  if the enthaly change in forward direction is ( -726.5 kj )   then enthalpy change in the reverse direction must be ( +726.5 Kj)