When 8.00 × 1022 molecules of ammonia react with 7.00 × 1022 molecules of oxygen according to the chemical equation shown below, how many grams of nitrogen gas are produced?
4 nh3(g) + 3 o2(g) → 2 n2(g) + 6 h2o(g)

1.848 g

Explanation: To calculate the moles, we use the equation:

   ....(1)

For ammonia:

Putting values in above equation, we get:

For the reaction:

By Stoichiometry of the reaction,

4 moles of ammonia combine with 3 moles of Oxygen

Thus 0.132 moles of ammonia will combine with= of oxygen

Thus ammonia is the limiting reagent as it limits the formation of product.

4 moles of ammonia produces 2 moles of nitrogen

0.132 moles of ammonia will produce= of nitrogen

Molar mass of nitrogen =  28 g/mol

Amount of nitrogen produced=

level 4 to level 2 : ))