What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?

M = 2.76 M

Explanation:

To calculate the molarity of any solution, we need to use the following expression:

M = n/V  (1)

Where:

M: Molarity of solution (mol/L or M)

n: moles of NH3 (moles)

V: volume of solution (In Liters)

But we do not have the moles of NH3, so it needs to be calculated. We have the mass and we can use the following expression to calculate the moles:

n = m/MM (2)

Where:

m: mass of NH3 (g)

MM: molar mass of NH3 (g/mol)

The reported molar mass of NH3 is 17.031 g/mol, so, using the mass of NH3 and this MM, we can calculate the moles:

n = 2.35 / 17.031 = 0.138 moles

With these moles, we can calculate the molarity:

M = 0.138 / 0.05

M = 2.76 mol/L

And this is the concentration or molarity of the NH3 solution.

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).