Find the empirical formula of a compound containing 53.70% iron and 46.30% sulfur

SThe  empirical  formula  is  calculated  as  follows

calculate  the  moles  of   each  element
moles=   %  composition/molar  mass  of  element

that  is  iron (Fe)  = 53.70/55.86 =  0.96  moles
   Sulfur  (s)=  46.30/32.07=  1.44  moles

calculate  the  mole  ratio  by diving   each  mole  by  smallest  mole(0.96)

that is  Fe  =  0.96/0/96 =1
            S=  1.44/0/96 =  1.5

multiply  by  2  to  remove   decimal

that  is    Fe =   1  x  2 =2
                S=  1.5  x2 =  3

the  empirical  formula  is  therefore  =  Fe2S3

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.