A1.0 l buffer solution is 0.12 m in hno2 and 0.060 m in kno2. which action destroys the buffer? part a adding 0.060 mol of kno2 adding 0.060 mol of koh adding 0.060 mol of hno3 none of the above

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

c. 4.54 x 10–12 j happens to be correct