Ahydrogen atom orbital has n=5 and ml=−2 .what are the possible values of l for this orbital?

Answer : There are three possible values of 'l' which are 2, 3 and 4.

Solution : Given,

n = 5

There are 4 quantum numbers :

        values are 1, 2, 3, 4, .........

        values are 0 to (n-1)

        values are +l to -l

        values are to

when n = 5 then the value of l are,

l = 0, 1, 2, 3, 4

At l = 0,  

At l = 1,  

At l = 2,  

At l = 3,  

At l = 4,  

So, when then the possible values of l are,

l = 2, 3, 4

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