Iron reacts with oxygen to produce iron(iii) oxide.4 fe(s) + 3 o2(g) → 2 fe2o3(s)if 6.4 moles of fe react with excess o2, how many moles of fe2o3 can be formed? a. 1.6 molb. 2.4 molc. 3.2 mold. 4.3 mole. 6.4 mol

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

imma come back to you hold on