If a compound containing only magnesium and oxygen consists of 0.564 g mg and 0.376 g o, what is the compound's empirical formula..

    the   Empirical  formula    of  the  compound  is  calculated    as  follows

find  the  moles  of  each  element
moles =  mass/molar  mass

that  is Magnesium= 0.564 g /24 g/mol  = 0.0235  moles

For  oxygen    =  0.376 g /16 g/mol=  0.0235  moles
find  the   mole  ratio  by  dividing   both     moles  of  by  0.0235 moles

magnesium =  0.0235/0.0235= 1mole
oxygen=  0.0235 /0.0235= 1mole

therefore  the  empirical    formula  =  MgO

The answer is probably c. xylem