What is the ph of a solution which is 0.025 m in weak base and 0.037 m in the conjugate weak acid (ka = 7.1 × 10–6)?

Hello!

This question can be solved using the Henderson-Hasselbach equation, but first we need to know the value of pKa

pKa= -log(Ka)= -log(7,1*10⁻⁶)=5,15

Now, we apply the equation:



So, the pH of this solution would be 4,98

Have a nice day!

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