To neutralized 1.65g lioh, how much .150m hcl would be needed?

0.458 liters of HCl will be needed to neutralize LiOH.

Explanation: Reaction follows:

Stoichiometry ratio of LiOH and HCl is 1 : 1

which means, 1 mole of LiOH reacts with 1 mole of HCl.

Number of moles can be calculated by

mass of LiOH = 1.65g (Given)

molar mass of LiOH = 24g

Number of moles = 0.06875 moles

Number of moles of LiOH =  Number of moles of HCl

Moles of HCl = 0.06875 moles

and  

Molarity = 0.15 moles/Liter (Given)

Volume needed to neutralize LiOH will be,

Volume of HCl needed to neutralize LiOH = 0.458 litre.

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

6.4 cm (max) - 25 cm (min)