What is the volume occupied by 0.118 mol of helium gas at a pressure of 1.05 atm and a temperature of 322 k?

  The  volume  occupied  by  0.118mol  of He  gas  at  a pressure of  1.05 atm  and  temperature  of  322k  is  calculated   by  use  of   ideal  gas    equation

that  is  PV = nRT
P(Pressure)1.05 atm
v(volume)=?
n  (number  of  moles)=0.118 mol
T(temperature)= 322K

from  equation  above volume(v)= nRT/p

volume(v) =  (0.118 mol  x  0.0821 L.atm/k.mol x322k)  / 1.05 atm =  2.97  L

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)