Calculate the ph of a buffer solution that contains 0.25 m benzoic acid (c6h5co2h) and 0.15 m sodium benzoate (c6h5coona). (ka = 6.5 × 10–5 for benzoic acid)

Hello!

To solve this problem we'll use the Henderson-Hasselbach equation, but first we need the vale for the pKa of Benzoic acid, which is pKa= -log(Ka)=4,19

Now, we apply the equation as follows:



So, the pH of this solution of Sodium Benzoate and Benzoic Acid is 3,97

Have a nice day!

Tropical easterlies is mostly likely your answer correct me if i’m wrong