23492u undergoes alpha decay. what is the atomic number of the resulting element. express your answer numerically as an integer.

Explanation:

It is known that an alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is or .

Therefore, when undergoes alpha decay then the reaction will be as follows.

Hence, the resulting element formed is thorium.

Therefore, we can conclude that atomic number of the resulting element is 90.      

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

particle   p is an electron and particle q is a neutron