99 points chemistry homework a sample of ammonia liberates 5.61 kj of heat as it solidifies at its melting point. what is the mass of the sample? δhsolid = -5.66 kj/mol.

5.61kJ*(1mol/5.66kJ)=0.991 mol NH3
Molar mass NH3= M(N)+3M(H)=14.0+3*1.0=17.0 g/mol
0.991 mol NH3*17.0g/1molNH3 ≈16.8 g NH3

I think the answer is 5.61kJ*(1mol/5.66kJ)=0.991 mol NH3
Molar mass NH3= M(N)+3M(H)=14.0+3*1.0=17.0 g/mol
0.991 mol NH3*17.0g/1molNH3 ≈16.8 g NH3

So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.

Neither model is able to show the reactivity of potassium.