4.5 moles of sodium sulfate contain how many atoms of sulfur

Chemical Formula of Sodium Sulfate is Na₂SO₄.

As we know, 1 mole of any substance contains 6.022 × 10²³ particles. So, 1 mole of Na₂SO₄ also contains 6.022 × 10²³ formula units of Na₂SO₄.
Also,
                     1 mole of Na₂SO₄ contains  =  6.022 × 10²³ Atoms of S
So,
            4.5 moles of Na₂SO₄ will contain  =  X atoms of S

Solving for X,
                                X  =  (4.5 moles × 6.022 × 10²³ Atoms) ÷ 1 mole

                                X  =  2.70 × 10²⁴ Atoms of S
Result:
            4.5 Moles of Na₂SO₄ contains 2.70 × 10²⁴ Atoms of Sulfur.

The answer is b on plato.