What is the molarity of a hydrochloric acid solution prepared by diluting 200.0 ml of 0.500m hcl to a total volume of 1.00 l?

The  molarity  of HCl  prepared by  diluting 200.0 ml of 0.5 M  HCl  to  a  total  volume  of  1.00 L  is  calculated  using the following  formula

M1V1=M2V2
M1=  200 ml
V1= 0.5 M
M2=?
V2= 1.00 L =  1x 1000 = 1000ml

M2  is therefore =  M1V1/V2

that is  0.5M  x 200 ml/1000 Ml = 0.1 M