14kmno4 + 4c3h5(oh)3 7k2co3 + 7mn2o3 + 5co2 + 16h2o how many moles of kmno4 are consumed to form 0.886 moles of carbon dioxide?

The balanced equation is given as;
14KMnO₄ + 4C₃H₅(OH)₃ → 7K₂CO₃ + 7Mn₂O₃ + 5CO₂ + 16H₂O
      14                           :                                             5

The formed moles of CO₂ = 0.886 mol

The stoichiometric ratio between CO₂ and KMnO₄ is 5 : 14

Hence,
 moles of CO₂ / moles of KMnO₄ = 5 / 14
  0.886 mol     / moles of KMnO₄ = 5 / 14
                        moles of KMnO₄  = 0.886 mol x 14 / 5
                        moles of KMnO₄  = 2.4808 mol

hence, consumed KMnO₄  moles = 2.4808 mol 

The answer would be true