What is the limiting reactant if 4.0 g of nh3 react with 8.0 g of oxygen?

              Oxygen is the Limiting Reagent

The Balance Chemical Equation is as follow,

                             4 NH₃  +  5 O₂     →      4 NO  +  6 H₂O

Finding the Limiting Reagent;

According to Balance equation,

               68.12 g (4 mol) NH₃ reacts with  =  160 g (5 mol) of O₂

So,

                      4.0 g of NH₃ will react with  =  X g of O₂

Solving for X,

                       X  =  (4.0 g × 160 g) ÷ 68.12 g

                       X  =  9.40 g of O₂

It means 4.0 g of NH₃ requires 9.40 g of O₂, while we are provided with 8.0 g of O₂ which is limited. Therefore, O₂ is the limiting reagent and will control the yield of products.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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