Consider the rate below r=k(l)^2(xy) what is the overall order of the reactants in this reaction? 0 1 2 3

The Order of Reaction is defined as, "the sum of the exponents of the concentration terms in the rate expression of the reaction".
The rate expression given is,

                                    Rate  =  k [L]² [XY]
So,
The sum of exponents is,
                                         2 + 1 = 3

It is a third order reaction, provided it is second order with respect to concentration of L and first order with respect to concentration of XY.

Result:
          It is 3rd Order Reaction.

What are the choices?