How many grams of lithium are needed to produce 45.0 grams of lithium nitride, according to the following process? 6 li(s) + n2(g) → 2 li2n(s)

             33.41 g of Li

Solution:

The Balanced Chemical equation is ,

                              6 Li(s) + N₂ (g)    →    2 Li₂N (s)

According to equation,

      55.76 g (2 mole) Li₂N is produced from  =  41.4 g (6 mole) Li
So,
              45 g of Li₂N will be produced from  =  X g of Li

Solving for X,
                                X  =  (45 g × 41.4 g) ÷ 55.76 g

                                X  =  33.41 g of Li

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