Calculate the energy transferred in joules when 29.5g of liquid water decreases from 14c to 0.0c

The  energy transferred  in joules  is   calculated  using the below  formula

Q(heat energy) =  M(mass)  x C (specific  heat capacity )  x  delta T(change  in  temperature
delta T =  0. 0c-  14 c  =  -14 c
M= 29.5 g
C of  water is always =  4.18  j/g/c

= 29.5 g x  -14 c x 4.18 j/g/c =-1726.34  joules are  needed when  29.5 g  of  liquid  water  decrease  from  14 c  to  0.0  C