Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is 1.86°c/m. remember to include the value of i.

Answer : The freezing point of a solution is,

Explanation :

First we have to calculate the Van't Hoff factor (i) for .

The dissociation of will be,

So, Van't Hoff factor = Number of solute particles = = 1 + 1 = 2

Now we have to calculate the freezing point of a solution.

Formula used for lowering in freezing point :

or,

where,

= change in freezing point

= temperature of solution = ?

= temperature of pure water =

= freezing point constant  =

m = molality  = 0.08500 m

i = Van't Hoff factor = 2

Now put all the given values in this formula, we get the freezing point of a solution.

Therefore, the freezing point of a solution is,

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the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.