Asample of o2 occupies a volume of 600 ml. if the pressure exerted on the o2 is tripled with the temperature remaining constant, the new volume of the oxygen is

For 1 mole of an ideal gas, we have PV=RT............(Eq. 1)
where, P = pressure
V= volume
R = universal gas constant
T = Temperature

Let, P1, V1 and T1 be initial pressure, volume and temperature of  respectively

Let, P2, V2 and T2 be pressure, volume and temperature of respectively, after application of pressure.

Using Eq. 1 we get,  ....... (Eq. 2)

Now, since that T1=T2 and P2=3(P1)

∴ Eq. 2 becomes P1V1=P2V2
∴ 
∴ V2 =  V1

Thus, final volume V2 will be 1/3 of initial volume V1

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