Chemistry, 21.07.2019 07:30 emilyanneK236
What is the emf of a cell consisting of a pb2+ / pb half-cell and a pt / h+ / h2 half-cell if [pb2+] = 0.83 m, [h+] = 0.064 m and ph2 = 1.0 atm ?
Answers: 1
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/ ![E^{0}cell - \frac{0.059}{n}log \frac{1}{[Pb^2^+]X[H^+]^2}](/tpl/images/0114/7789/ce948.png)
![E^{0}cell = 0.126 v\\∴Ecell = 0.126 - \frac{0.059}{2}log \frac{1}{[0.83]X[0.064]^2}](/tpl/images/0114/7789/5add0.png)
![emf=-0.126\;-\dfrac{0.059}{2}\;\times\;log\;\dfrac{1}{[0.83]\;\times\;[0.064]^2}\\ emf=0.0532\;\text V](/tpl/images/0114/7789/fcd3d.png)
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What is the emf of a cell consisting of a pb2+ / pb half-cell and a pt / h+ / h2 half-cell if [pb2+]...
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