(tco 4) what will the following program segment display? int funny = 7, serious = 15; funny = serious % 2; if (funny ! = 1) { funny = 0; serious = 0; } else if (funny == 2) { funny = 10; serious = 10; } else { funny = 3; serious = 3; } cout < < funny < < " " < < serious < < endl; }

3 3

Explanation:

The operator modulus '%' is gives the reminder of the number.

for example:

7%2  it gives the result 1 because 1 is reminder after divided by 2.

Initially the value of funny is 7 and serious is 15.

then, 15 is modulus by 2 which gives 1 and it store in the funny.

After that, if else statement check for condition.  

funny != 1  this condition is FALSE because Funny is equal to 1.

it moves to else if part Funny == 2 condition again FALSE it then move to else part and execute the statement Funny contain 3 and serious contain 3.

and then display.

Therefore, the answer 3 3.

answer; ///i do believe that the correct answer is (condition and action); /