Write a program which get interger numbers and make it in reverse order.

#include <iostream>

using namespace std;

int main()

{

   int num,a,digit;

   a=0;

   cout<<"Enter the number"<<endl;

   cin>>num;

   while(num>0)

   {

       digit=num%10;

       a=a*10+digit;

       num/=10;

   }

   cout<<"Reversed number is "<<a<<endl;

return 0;

}

Explanation:

Taking input of an integer num.

Initializing an integer a with value 0.

looping over n while it is greater than zero.

By using modulus operator(%) we will get the last digit.

Storing the digit in a.

Dividing num by 10;

After the loop is over we will get the answer in a.

incoplete qest

explanation:

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