What does the following statement do if usernumber has an integer value of 14 and userentry has a string value of “two”? usernumber = integer. parseint(userentry); a. throws an exception b. converts “two” to “2” and stores it in userentry c. converts “two” to 2 and stores it in usernumber d. stores a null value in usernumber

The correct answer for the given question is option(A) i.e  Throws an exception .

Explanation:

following are the code in java language

public class Main

{

 public static void main (String[]args)

 {

int userNumber =14;

String userEntry="two";

userNumber= Integer.parseInt(userEntry);

System.out.println(userNumber);

 }

}

The main class throws an  EXCEPTION  java.lang.NumberFormatException

because we cannot convert the string  userEntry into integer.

output

Exception in thread java.lang.NumberFormatException

yes the ansewer is c bc you can look it up!

answer; receiver;