Show that there exists a 7-ary (8,m,4)-code, where m > 200.
to the nearest whole number, calculate the best lower bound for
m = a7(8,4) as determined by the sphere covering bound.

It's ✌✌✌✌✌✌

It is called "choke.

Public static int mystery(int a[], int x) {     int c = 0;     for(int i = 0; i < a.length; i++) {        if (a[i] == x) c++;     } return c; }the method counts how many times an integer shows up in an integer array.the c variable is declared in the method to keep track of how many times the certain value has shown up.the for-loop loops through the entire array.the line    if (a[i] == x) c++;   checks if each element of the array is equal to the inputted integer to check. for each number in the array that is equal to the inputted integer x, the c variable will be incremented by 1. otherwise it will do nothing.then c is returned at the end of the loop.for example, if we have, in the main method with the mystery method coded in the class:     int arraytest[] = {2, 23, 23, 23, 3};     int testme = 23;     int count = mystery(arraytest, testme);     system.out.println(count); then the print out will be    3 because there are three 23s in that array.

This printout will be      akes======in java, somestring.substring(a,b) will return a portion of somestring, including index a and up to but not including index b.in java, string indexes start from 0. the very first character has an index of 0.for  shakespeare, we have    "shakespeare".substring(2,6); gets us "akes"