If a disk drive has 8 surfaces and there are 1024 tracks per surface with 256 sectors per track and 512 bytes/sector. what is the capacity of the drive?

Capacity of the drive equals 1073741824 bytes.

Explanation:

Since it is given that there are 8 surfaces with 1024 tracks per surface thus the number of tracks in 8 surfaces equals

Now since it is given that there are 256 sectors per track thus the number of sectors in 8192 tracks equals

Now since it is given that there are 512 bytes per sector thus the number of bytes in 2097152 sectors are

Thus the number of bytes in the memory equals 1073741824 bytes.

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explanation:

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