Now suppose there are two ftp file streams between two different clients and two different servers established at the same exact time over the same link. one stream is using a 1460 byte segment size the other a 576 byte segment size. assume there are no drops and both streams are using a standard tcp and ip header. assume both ftp streams are copying the same 3 mib file (using the binary mb unit).
a. how many segments will be generated by the stream that is using the 1460 byte segment size?
b. how many bytes of the file will be in the last segment?
c. how many segments will be generated by the stream that is using the 576 byte segment size?
d. how many bytes of the file will be in the last segment of the second stream?

Write a new lc-3 trap subroutine (i.e. a subroutine that will be invoked via the trap instruction) that will receive a numeric digit entered at the keyboard (i.e. an ascii character), echo it to the screen, and return in r0 the corresponding numeric value: so if the user types the digit '7', the character '7' will appear on the screen, but the value returned in r0 will be b0000 0000 0000 0111 (#7) you may not use any trap calls in your code - you must implement the "polling" code that interrogates the keyboard status and data registers. ; getnum_tsr ; a subroutine for obtaining a numeric value ; given ascii numeric digit input to keyboard. ; the numeric digit is echoed to the console (e.g. '7' = b0000 0000 0011 0111), ; but the value returned in r0 is the actual numeric value ; corresponding to the digit (e.g. b0000 0000 0000 0111 =