Print "censored' if userlnput contains the word "darn, else print userlnput. end with newline. ex: if userinput is "that darn cat., then output is: censored ex: if userlnput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report program end never reached. the system doesn't print the test case that caused the reported message. 1 import java. util. scanner; 3 public class censoredwords 4public static void main ( 1 test passed string args) scanner scnr -new scanner(system. in); string userinput; a tests passed userinput scnr. nextline); 10 your solution goes here 12 13 run

The code is given below in Java with appropriate comments

Explanation:

//Import the input.

import java.util.Scanner;

class CensoredWords

{

    //Define the main method.

    public static void main(String args[ ])

    {

         //Define the variables.

         String userInput="" ;          

         //Define the scanner object

         Scanner scobj = new Scanner(System.in);

          //Accept the userInput.

         System.out.print("Enter String: ");

         userInput=scobj.nextLine();

         //Check if the input contains darn.

         //Print censored.

         if(userInput.toUpperCase().indexOf("DARN") != -1)

         System.out.printf("Censored");

         //IF the input does not contains darn

         //Print userInput.

         else

System.out.printf(userInput)

         return;

}

}

check the image attached

some main parts enter backspace caps lock shift and ctrl

i'm so sorry that's not a question and this isn't an answer