The operation:
pstruct -> member
is equivalent to
a. (*pstruct).member
...
Computers and Technology, 21.09.2019 18:10 wig77777
The operation:
pstruct -> member
is equivalent to
a. (*pstruct).member
b. & pstruct. member
c. *pstruct. member
d. (& pstruct).member
Answers: 2
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