Write a program that accepts a number as input, and prints just the decimal portion.

There are 2 ways to do extract the decimal part:

Explanation:

int main() {

 double num = 23.345;

 int intpart = (int)num;

 double decpart = num - intpart;

 printf(""Num = %f, intpart = %d, decpart = %f\n"", num, intpart, decpart);

}

#include <stdlib.h>

int main()

{

   char* inStr = ""123.4567"";          

   char* endptr;                      

   char* loc = strchr(inStr, '.');

   long mantissa = strtod(loc+1, endptr);

   long whole = strtod(inStr, endptr);  

   printf(""whole: %d \n"", whole);      

   printf(""mantissa: %d"", mantissa);  

}

The program to this question can be given as:

Program:

#include <iostream> //header file

using namespace std;

void cal(double number) //defining method cal

{

double decimal_part; //defining variable

int integer_part; //defining variable

integer_part = (int)number; //type casting

decimal_part = number - integer_part;  //holding decimal value

cout<<"number you inserted :"<<number<<endl;  //print value

cout<<"integer part :"<<integer_part<<endl;  //print integer part

cout<<"decimal part :"<<decimal_part<<endl; // print decimal part

}

int main()  //defining main method

{

double number; //defining variable number

cout<<"Input floating point number :"; //message

cin>>number; //taking input from user

cal(number); //calling function and passing value in function

return 0;  

}

Output:

Input floating point number :786.786

number you inserted :786.786

integer part :786

decimal part :0.786

Explanation:

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