Write a c program that counts the number of repeated characters in a phrase entered by the user and prints them. if none of the characters are repeated, then print "no character is repeated" for example: if the phrase is "full proof" then the output will be number of characters repeated: 3 characters repeated: f, l, o note: assume the length of the string is 10.

#include <stdio.h>

int main() {

   char phrase[10];//declaring a string.

   printf("Enter the phrase\n");

   scanf("%[^\n]s",phrase);//taking a phrase as an input with spaces.

   int a[256]={0};//count array.

   for(int i=0;phrase[i]!='\0';i++)

   {

       a[phrase[i]]++;//updating the count.

   }

   for(int i=0;i<256;i++)

   {

       if(a[i]>1)//printing the characters having count greater than 1.

       {

           printf("%c ",i);

       }

   }

return 0;

}

Output:-

Enter the phrase

full proof

f l o

Explanation:

In the code written above I have declared a string phrase and then taking input from the user in the string phrase with white spaces.Then I have created a count array for the storing the frequency of the characters and then looping over the array a and if there any element is greater than 1 means frequency is greater than 1 then printing that character.