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Computers and Technology, 18.10.2019 04:20 tfyvcu8052
Given h = sha256(m ∥ k), where k is a secret and "∥" means concatenation (no padding is involved in calculating h). can you calculate sha256(x ∥ k) for a different message x without knowing k?
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Given h = sha256(m ∥ k), where k is a secret and "∥" means concatenation (no padding is involved in...
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