Write a program that reads a list of integers, and outputs those integers in reverse. the input begins with an integer indicating the number of integers that follow. for coding simplicity, follow each output integer by a space, including the last one. assume that the list will always contain less than 20 integers.

The program to this question as follows:

Program:

#include <stdio.h> //header file.

int main() //main method.

{

const int size= 20; //define variable.

int a[size]; //define array

int i, n; //define variable

printf("Enter number of elements :"); //message.

scanf("%d", &n);//input size of array.

printf("Enter array elements :"); //message

for (i = 0; i < n; ++i) //loop

{

scanf("%d",&a[i]); //input array elements by user.

}

printf("Reverse order :\n");

for (i = 0; i < n; ++i) //loop

{

printf("%d ",a[n-i-1]); //print elements in reverse order.

}

return 0;

}

Output:

Enter number of elements :5

Enter array elements :5

4

3

2

1

Reverse order :

1 2 3 4 5  

Explanation:

The description of the above program as follows:

In the program firstly we include the header file and define a method that is "main method" in the method we define variables that are "size, n, i, and a[]".  The size variable is used to make a variable constant that means its value will not change in the program. We pass the size variable value to the array and use i variable for loop. We use variable n and a[] for user inputs. In n variable, we input a number of elements to be inserted into an array and a[] we insert all array elements to insert these elements we use for loop. Then we define another for loop in this loop we print all array elements in reverse order.

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