In java :
write code to print the location of any alphabetic character in the 2-character string passcode. each alphabetic character detected should print a separate statement followed by a newline. ex: if passcode is "9a", output is: alphabetic at 1import java. util. scanner; public class findalpha {public static void main (string [] args) {scanner scnr = new scanner(system. in); string passcode; passcode = scnr. next(); /*your solution goes here */}}

The code segment is an illustration of conditional statements

Conditional statements are statements whose execution depends on the truth value of the condition.

The code segment in Java, where comments are used to explain each line is as follows:

//This checks if the first character is an alphabet.

if (Character.isLetter(passCode.charAt(0))){

   //If yes, this prints alphabetic at 0

   System.out.println("Alphabetic at 0");

}

//This checks if the second character is an alphabet.

if (Character.isLetter(passCode.charAt(1))){

   //If yes, this prints alphabetic at 1

   System.out.println("Alphabetic at 1");

}

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The code to this question can be given as:

Code:

//define code.

//conditional statements.

   if (Character.isLetter(passCode.charAt(0))) //if block

   {

       System.out.println("Alphabetic at 0"); //print message.

   }

   if (Character.isLetter(passCode.charAt(1))) //if block

   {

       System.out.println("Alphabetic at 1"); //print message.

   }

Explanation:

In this code, we define conditional statement and we use two if blocks. In both if blocks we use isLetter() function and charAt() function. The isLetter() function checks the inserted value is letter or not inside this function we use charAt() function that checks inserted value index 1 and 2 is the character or not.

the answer will be d