For the following code sequence, fill in the instructions or operands that are missing from the code sequence and marked with '(number)' - there are 5 blanks; label your answer 1, 2, 3, 4, 5.
; ; counts the number of times a character occurs in a string
; ; and store value on "result"
; ; character -- stored at x6000
; ; string -- stored at x7000
; ; result -- stored at x8000
.orig x3000
nmchr and r0,r0,#0
ld r1,afile ; ; r1 has address of the string (file in memory)
ldi 1 ; ; r2 has the value of the character
not r2,r2
2 r2,r2,#1 ; ; 2's complement of character
aloop ldr r3,r1,#0
3 stop ; ; leave loop on zero word
add r3,r3,r2
brnp nocount
add 4
nocount add r1,r1,#1
5 aloop
stop sti r0,acount ; ; count is stored
halt
achar .fill x6000
afile .fill x7000
acount .fill x8000
.end