Write a method called all less that accepts two arrays of integers and returns true if each element in the first array is less than the element at the same index in the second array. for example, if the two arrays passed are {45, 20, 300} and {50, 41, 600}, your method should return true. if the arrays are not the same length, you should return false. test your method and print out to the screen in main() function the following callsa. all less(arr1, arr2); (where arr1 = [1,2,3,4,5], arr2 = [4,5,6,7,8])b. all less(arr1, arr2); (where arr1 = [1,2,3,4,5], arr2 = [5,6,7,8])c. all less(arr1, arr2); (where arr1 = [5,2,3,4,1], arr2 = [4,5,6,7,8])d. all less(arr1, arr2); (where arr1 = [5,5,3,4,5], arr2 = [9,9,9,9,1])

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess  

{

int a,b; //define variable

a=  *(&arr1 + 1) - arr1; //hold length of arr1

b=  *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition  

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

}

return 0; //return value

}

int main() //define main method.

{

   int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

   int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

   cout<< allLess(arr1,arr2); //function calling

   return 0;

}

Output:

1

Explanation:

The Explanation of the C++ language program can be given as follows:

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