What is the output of the following program? #include using namespace std; void dosomething(∫); int main(){int x = 2; cout < < x < < endl; dosomething(x); cout < < x < < endl; return 0; }void dosomething(int & num){num = 0; cout < < num < < endl; }

The outputs of the code is

2

0

2

Explanation:

First, I'll arrange the code line by line. While arranging the code, I'll make some corrections

#include <iostream>

using namespace std;

void doSomething();

int main(){

int x = 2;

cout << x <<endl;

doSomething(x);

cout << x << endl;

return 0;

}

void doSomething(int &num)

{

num = 0;

cout << num << endl;

}

At line 6, the value of x which is 2 is printed and the line is terminated to prevent printing of value on the same line. So, the next print statement will start on the next line.

At line 7, the function doSomething () is called.

This statement will execute the instructions in the doSomething () function and print value 0. This line is also terminated.

At line 8, the value of x is printed which is also 2

in software engineering and computer science, abstraction is: the process of removing physical, the way that different data types interact, is the beginning of abstraction.

(because i need 20 chars)