Given the function definition void something ( int a, int& b ) { int c; c = a + 2; a = a* 3; b = c + a; } what is the output of the following code fragment that invokes something? (all variables are of type int.) r = 1; s = 2; t = 3; something(t, s); cout < < r < < ' ' < < s < < ' ' < < t < < endl;

1 14 3

Explanation:

If that code fragment is put under a main() function and then it will yield the above output. According to the function something(), only changes in value second parameter will be reflected and first will be unchanged because second is passed by reference and the first one is passed as value so only address of 's' is passed, so, only its value is changed and the rest are same.

a hotel that serge might be staying in

solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.